50=-16x^2+112x

Solution for 50=-16x^2+112x equation:

50=-16x^2+112x

We move all terms to the left:

50-(-16x^2+112x)=0

We get rid of parentheses

16x^2-112x+50=0

a = 16; b = -112; c = +50;
Δ = b2-4ac
Δ = -1122-4·16·50
Δ = 9344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9344}=\sqrt{64*146}=\sqrt{64}*\sqrt{146}=8\sqrt{146}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-8\sqrt{146}}{2*16}=\frac{112-8\sqrt{146}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+8\sqrt{146}}{2*16}=\frac{112+8\sqrt{146}}{32}
$